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Saturday, January 26, 2008
Pre-Calculus
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7 comments:
how do i find the domain and range of a function, for instance f(x)=-5x^2+1x+5
I'm pretty sure the domain is -infinity to infinity but the range is screwing me up
It's good that you know that the domain of the function is infinity to infinity since there's no restriction on the x values. Using the same logics and reasoning, the range is infinity to infinity also because there's no restriction on the output, which is f(x).
how do i find the domain of a square root fnction: f(x): square root of 4-x^2?
First, because f(x) is a square root function, therefore f(x) must equal or greater than 0, which means
4 - x^2 = 0
x^2 = 4
x = + or - 2
+2 and -2 are the critical numbers.
1: If x is > 2, then sqrt of
4 - x^2 is less than 0, therefore x is not > 2.
2: If x is < -2, then sqrt of
4 - x^2 is also less than 0, therefore x is not < -2.
finally, for -2 < x < 2, square root of 4 - x^2 is equal or greater than zero. Therefore, the domain of f(x) is -2 < x < 2.
how do u find the range of square root of x^2-5X-6?
How do I find all the values t such that 5-7t is greater than or equal to 0?
How do I find the domain ?
f(x)= √s-1/ s-4
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